2019 Waec Physics Obj and Theory Questions and Answers

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(10a)

Atomic spactra is the spectra of frequencies of electromagnetic radiation emitted or absorbed during transitions of electrons between energy levels within an atom.
Typing in progress….
(9ii)

  1. Temperature . As the temperature increases, the rate of evaporation also increases.
  2. Surface Area . As the Surface area increases, the rate of evaporation increases.

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( 9a)

i) latent heat is the heat required to convert a solid into a liquid or vapour, or a liquid into a vapour, without change of temperature.

ii)

√ temperature
√ humidity

9b

CODED_TEAM
8ai Terminal velocity is the highest velocity attainable by an object as it falls through a fluid (air is the most common example). It occurs when the sum of the drag force ( Fd ) and the buoyancy is equal to the downward force of gravity (F G ) acting on the object. Since the net force on the object is zero, the object has zero
acceleration . [1]
In fluid dynamics , an object is moving at its termin
(9b)
(i) Clay is proper conductor of heat than plastic

(ii) An in pressure in the cooker increases the ambient temperature in the cooker, hence the food cooks faster

(9c)
Change in the state of a substance
Increase in temperature
11) u= 5ms-1 u= 6ms-1
A= 1ms-2 a= 3ms-2
p→ ←a

M—————————————N
51m

11a)t when particles are 30 meters apart
S= ut + ½ at2
Sp= st + ½ t2
Sa = 6t + 1/2 (3)t2
Where sp and sa are distances covered by particles respectively at any time t
At time, t= 1.5s
Sp = 5(1.5) + ½(1.5)2 =8.625m
sa = 6(1.5) + ½ (3)(1.5)2 = 12.375m
sp + sa = 8.625 + 12.375
= 21m
Distance between particles = 51 – 21 = 30m
At time t = 1.5s, the particles will be 30 meters apart.
(5)
Draw the diagram

Using cosine law
Cos∅ = 16²+10²-14²/2(16)(10)

Cos∅ = 256 + 100 – 196/320

Cos∅ = 160/320
Cos∅ = 0.5
∅ = cos-¹(0.5)
∅ = 60°

Angle between 10N and 16N
= 180 – ∅ (sum of angles on a straight line)
= 180 – 60
=120°
(1)
Mass = 20g = (20/100)kg = 0.02kg
Extension = 5cm = (5/100)m = 0.05m
K = 200N/
V = ?
1/2mv² = 1/2ke²
V = √ke²/m = √200×0.05×0.05/0.02
V = √25
V = 5m/s
8aii density
Viscosity of medium
Temperature
(3)
(i) magnetic declination
(ii) magnetic inclination
(iii) horizontal components
11a)t when particles are 30 meters apart
S= ut + ½ at2
Sp= st + ½ t2
Sa = 6t + 1/2 (3)t2
Where sp and sa are distances covered by particles respectively at any time t
At time, t= 1.5s
Sp = 5(1.5) + ½(1.5)2 =8.625m
sa = 6(1.5) + ½ (3)(1.5)2 = 12.375m
sp + sa = 8.625 + 12.375
= 21m
Distance between particles = 51 – 21 = 30m
At time t = 1.5s, the particles will be 30 meters apart.

WAEC PHYSICS)

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